stożek 1
r = 3
H = 10
Pp=\pi r^2=\pi *3^2=9\pi
V=Pp*H=9\pi *10=90\pi
2)
r = 6
V = 72\pi
Pp=\pi r^2=\pi *6^2=36\pi
V=Pp*H
H=\frac{V}{Pp}=\frac{72\pi}{36\pi}=2
stożek 3
H = 2
Pp=\pi
$\pi r^2=\pi$obustronnie|:\pi
r^2=1
r = 1
V=\pi r^2*H=\pi *1*2=2\pi
stożek 4
Pp = V
Pp*H=V
81\pi *H=81\pi obustronnie |:81\pi
H = 1
\pi r^2=81\pi |:\pi
r^2=81
r = 9
stożek 5
H = 12
V = 64\pi
Pp=\frac{V}{H}=\frac{64\pi}{12}=\frac{16\pi}{3}
Pp=\pi r^2
\pi r^2=\frac{16\pi}{3}|*3
3\pi r^2=16\pi|:\pi
3r^2=16
r=\sqrt{\frac{16}{3}}=\frac{4}{\sqrt3}=\frac{4\sqrt3}{\sqrt3*\sqrt3}=\frac{4\sqrt3}{3}