b)
(11\frac{1}{9})^{-\frac{1}{2}}-(-0,2)^{-3}*81^{-0,75}+(0,512)^{\frac{1}{3}} =\\\\= (\frac{100}{9})^{-\frac{1}{2}}-(-\frac{1}{5})^{-3}\cdot (3^4)^{-\frac{3}{4}}+(\frac{512}{1000})^{\frac{1}{3}}\\\\ =[(\frac{10}{3})^2)^{-\frac{1}{2}}-(-5)^3\cdot 3^{-3}+\frac{(2^9)^{\frac{1}{3}}}{(10^3)^{\frac{1}{3}}}\\\\ =(\frac{10}{3})^{-1}+(\frac{5}{3})^3+\frac{2^3}{10} \\\\ =\frac{3}{10}+\frac{125}{27}+\frac{8}{10}\\\\ =\frac{11}{10}+\frac{125}{27}\\\\ =\frac{297+1250}{270} \\\\=\frac{1547}{270}\\\\=5\frac{197}{270}