(\frac{25}{4})^{2x-1}=0,4^{3x-1}2
(\frac{25}{4})^{2x-1}=(\frac{2}{5})^{3x-12}
((\sqrt{\frac{25}{4}})^2)^{2x-1}=(\frac{2}{5})^{3x-12}
((\frac{5}{2})^2)^{2x-1}=(\frac{2}{5})^{3x-12}
((\frac{2}{5})^{-2})^{2x-1}=(\frac{2}{5})^{3x-12}
(\frac{2}{5})^{-4+2x}=(\frac{2}{5})^{3x-12}
-4x+2=3x-12
-4x-3x=-12-1
-7x=-14
x=2