Zadanie 5
a - bok kwadratu
Ob=4a
4a-1=d + d
4a-1=2d
4a-2=2a\sqrt2
4a-2a\sqrt2=2 \ |:2
2a-a\sqrt2=1
a(2-\sqrt2)=1
a=\frac{1}{2-\sqrt2}
a=\frac{2+\sqrt2}{(2-\sqrt2)(2+\sqrt2)}
a=\frac{2+\sqrt2}{4-2}
a=\frac{2+\sqrt2}{2}
{P=a^2=(\frac{2+\sqrt2}{2})^2=\frac{(2+\sqrt2)^2}{4}=\frac{4+4\sqrt2+2}{4}=\frac{6+4\sqrt2}{4}=\frac{\not2^1(3+2\sqrt2)}{\not4^2}=\frac{3+2\sqrt2}{2} \ [j^2]} jednostek kwadratowych