a) 3x^2+6-x^2-4
dla x=4\frac{1}{2}
b)
5y^2-3-2y^2+5
dla y=3\frac{1}{2}
a)
3x^2+6-x^2-4=2x^2+2=2(4\frac{1}{2})^2+2=
=2*(\frac{9}{2})^2+2=2*\frac{81}{4}+2=\frac{81}{2}+2=
=40\frac{1}{2}+2=42\frac{1}{2}
5y^2-3-2y^2+5=3y^2+2=
=3*(3\frac{1}{2})^2+2=3*(\frac{7}{2})^2+2=
=3*\frac{49}{4}+2
=\frac{147}{4}+2=36\frac{3}{4}+2=38\frac{3}{4}