Zadanie Oblicz: $\frac{1}{3}log125 + 3log2 - \frac{1}{2}$log16
źródło:
\frac{1}{3}log125 + 3log2 - \frac{1}{2}log16=log(5^3)^{\frac{1}{3}}+log2^3-log(2^4)^{\frac{1}{2}}=
=log5+log8-log2^2=log(5*8)-log4=log(40:4)=log10=1