b)
\frac{\sqrt[3]{0,375}*\sqrt[3]9+(3^{-1}-\sqrt[4]{\frac{16}{81}}}{[(\frac{81}{625})^{-0,75}:(1\frac{2}{3})^3-(0,125)^{\frac{1}{3}}]^{-2}}=
=\frac{\sqrt[3]{\frac{3*9}{8}}+(\frac{1}{3}-\frac{2}{3})^{-2}}{[(\frac{81}{625})^{-\frac{3}{4}}:(\frac{5}{3}^3-(\frac{1}{8})^{\frac{1}{3}}]^{-2}}=
=\frac{\sqrt[3]{\frac{27}{8}}+(-\frac{1}{3})^{-2}}{[\sqrt[4]{\frac{625}{81}}^3:(\frac{5}{3})^3-\sqrt[3]{\frac{1}{8}}]^{-2}}=
=\frac{\frac{3}{2}+9}{[(\frac{5}{3})^3:(\frac{5}{3})^3-\frac{1}{2}]^{-2}}
=\frac{10,5}{(1-\frac{1}{2})^{-2}}=
=\frac{10,5}{(\frac{1}{2})^{-2}}=10,5:4=2,625
lub wynik w postaci ułamka zwykłego
2\frac{5}{6}