zadanie 56
64^{\frac{1}{3}}=\sqrt[3]{64}=4
b)
81^{-\frac{1}{4}}=\frac{1}{\sqrt[4]{81}}=\frac{1}{3}
c)
3^{-\frac{1}{3}}=\frac{1}{\sqrt[3]3}=\frac{(\sqrt[3]3)^2}{\sqrt[3]3*(\sqrt[3]3)^2}=\frac{\sqrt[3]9}{3}
d)
e)
(2\frac{1}{4})^{\frac{1}{2}}=\sqrt{\frac{9}{4}}=\frac{3}{2}=1\frac{1}{2}
f)
125^{-\frac{1}{3}}=\frac{1}{\sqrt[3]{125}}=\frac{1}{5}
g)
(\frac{25}{49}^{-\frac{1}{2}}=\sqrt{(\frac{25}{49})^{-1}}=\sqrt{\frac{49}{25}}=\frac{7}{7}=1\frac{2}{5}
h)
256^{\frac{1}{4}}=\sqrt[4]{256}=4