zadanie 10 Oblicz
a)
\frac{\frac{\sqrt{2^4}}{2}-(\frac{3}{\sqrt2})^{-2}}{(\frac{\sqrt2}{3})^2*(\frac{1}{\sqrt2})^{-3}}=\frac{\frac{\sqrt{16}}{2}-(\frac{\sqrt2}{3})^2}{\frac{2}{9}*({\sqrt2})^3}=
\frac{\frac{4}{2}-\frac{2}{9}}{\frac{2}{9}*\sqrt8}=\frac{\frac{36-4}{18}}{\frac{2}{9}*2\sqrt2}=\frac{\frac{32}{18}}{\frac{4\sqrt2}{9}}=
\frac{16}{9}*\frac{9}{4\sqrt2}=\frac{4}{\sqrt2}=\frac{4*\sqrt2}{\sqrt2*\sqrt2}=
\frac{4\sqrt2}{2}=2\sqrt2