Zad. 106
a)
=(\frac{6}{10}*\frac{5}{3})^{-8}=1^{-8}=1
b)
=(\frac{12}{7}*\frac{7}{12})^{-2}=1^{-2}=1
c)
(3,75*1,6)^{-3}=6^{-3}=\frac{1}{216}
Zad. 107
b)
=\frac{1-10^1}{(3:8)^{-1}*(\frac{3}{2})^3-(-\frac{1}{3})^{-1}}=\frac{-9}{(\frac{8}{3})*\frac{27}{8}-(-3)^1}
=\frac{-9}{\frac{8}{3}*\frac{27}{8}+3}=\frac{-9}{12}=-\frac{3}{4}
c)
=\frac{[2-(\frac{4}{1})^1]}{(\frac{3}{8})^{-1}-(\frac{3}{5})^{-1}}=\frac{[2-4]^{-2}}{\frac{8}{3}-\frac{5}{3}}=\frac{(-2)^{-2}}{1}=(-\frac{1}{2})^2=\frac{1}{4}=0,25
d)
=\frac{(\frac{1}{5})^{-2}*(\frac{5}{3})^{-1}-(\frac{1}{3}-\frac{1}{2})^{-2}}{\frac{21}{2}}=
=\frac{25*\frac{3}{5}-(-\frac{1}{6})^{-2}}{\frac{21}{2}}=\frac{15-36}{\frac{21}{2}}=-\frac{21}{1}*\frac{2}{21}=-2