\frac{(1\frac{5}{6}+1\frac{19}{24})*\frac{16}{29}}{7\frac{1}{3}:2,2-2}=
=\frac{(1\frac{20}{24}+1\frac{19}{24})*\frac{16}{29}}{\frac{22}{3}*\frac{10}{22}-2}=
=\frac{2\frac{39}{24}*\frac{16}{29}}{\frac{10}{3}-2}=\frac{\frac{87}{24}*\frac{16}{28}}{3\frac{1}{3}-2}=
=\frac{2}{1\frac{1}{3}}=\frac{2}{1}*\frac{3}{4}=\frac{3}{2}