\frac{4}{3}x^2-\frac{(x+1)^2}{3}>\frac{(2x-1)^2}{4}-\frac{1}{2}
źródło:
\frac{4}{3}x^2-\frac{(x+1)^2}{3}>\frac{(2x-1)^2}{4}-\frac{1}{2}/*12
16x^2-4(x+1)^2>3(2x-1)^2-6
16x^2-4(x^2+2x+1)>3(4x^2-4x+1)-6
16x^2-4x^2-8x-4>12x^2-12x+3-6
16x^2-4x^2-12x^2-8x+12x>4+3-6
4x>1/:4
x>\frac{1}{4}
Odp.