Zadanie 1
x=-1
x^4-x^3+3x^5-x^3-5x-2=.
3x^5+x^4-2x^3-5x-2=
3\cdot (-1)^5+(-1)^4-2\cdot (-1)^3-5\cdot (-1)-2=
=-3+1+2+5-2=3
-----------
x=\sqrt2
3x^5+x^4-2x^3-5x-2=
=3\sqrt{2^5}+\sqrt{2^4}-2\sqrt{2^3}-5\sqrt2-2=
3\sqrt{16*2}+\sqrt{16}-2\sqrt{4\cdot 2}-5\sqrt2-2=
=3\cdot 4\sqrt2+4-2\cdot 2\sqrt2-5\sqrt2-2=
=12\sqrt2-4\sqrt2-5\sqrt2+2=
=3\sqrt2+2