[(3-√5)^{\frac{1}{2}} +(3+√5)^{\frac{1}{2}}]^{-2} * [(\frac{27}{8})^{\frac{1}{3}}-28^0] =
=([(3-\sqrt5)^{\frac{1}{2}}]^2-2[93-\sqrt5)(3+\sqrt5)]^{\frac{1}{2}}+
+[(3+\sqrt5)^{\frac{1}{2}}]^2 * [\sqrt[3]{\frac{27}{8}}-1]=
[3-\sqrt5-2\sqrt{9-5}+3+\sqrt5] * [\frac{3}{2}-1]=
[6-2 * 2] * [\frac{1}{2}]=2 * \frac{1}{2}=1