\frac{1,75+0,5\cdot (\frac{2}{3})^{-1}}{3\frac{1}{12}-3\cdot (\frac{2}{3})^2}=\\ =\frac{\frac{175}{100}+\frac{1}{2}\cdot \frac{3}{2}}{\frac{36}{12}-\not3^1\cdot \frac{4}{\not9^3}}=\\= \frac{\frac{7}{4}+\frac{3}{4}}{\frac{9}{3}-\frac{4}{3}}=\\ =\frac{\frac{10}{4}}{\frac{5}{3}}=\frac{10}{4}\cdot \frac{3}{5}=\frac{30}{20}=1,5