Zapisz w postaci sumy algebraicznej
(6x+5)^2=36x^2+60x+25
(\frac{1}{4}+8x)^2=\frac{1}{16}+4x+64x^2
(2x-1)^2=4x^2-4x+1
(3-\frac{1}{3}x)^2=9-2x+\frac{1}{9}x^2
(x-1)^3=x^3-3x^2+3x-1
(3x+5)^3=27x^3+3(3x)^2*5+3*3x*5^2+125=
=27x^3+135x^2+225x+125
(\frac{2}{3}x+6)^3=\frac{8}{27}x^3+3*(\frac{2}{3}x)^2*6+3*\frac{2}{3}x*6^2+6^3=
=\frac{8}{27}x^3+8x^2+72x+216
(2-\frac{1}{2}x)^3=8-3*2^2*\frac{1}{2}x+3*2*(\frac{1}{2}x)^2-\frac{1}{8}x^3=
=8-6x+\frac{3}{2}x^2-\frac{1}{8}x^3