(3x-4)+(2x-3)(x+1)-x(x-2)=3x-4+2x^2+2x-3x+2x-x^2+2x=x^2+6x
4x\sqrt{3}(\frac{1}{8}\sqrt{27}-0,75\sqrt{12})=4x\sqrt{3}(0,125\sqrt{27}-0,75\sqrt{12})=0,5x\sqrt{3}\sqrt{27}-3\sqrt{3}\sqrt{12}=0,5x\sqrt{3}\sqrt{3*9}-3\sqrt{3}\sqrt{3*4}=1,5x\sqrt{3}\sqrt{3}-6\sqrt{3}\sqrt{3}=1,5x*3-6*3=4,5x-18