czy tak wygląda zapis?
\left \{ {{\frac{2x-1}{2}-\frac{2y+1}{2}=3} (*2) \atop {(x-1)^2-2(y+2)=(x-1)(x+1)+y}} \right.
\left \{ {{2x-1-2y-1=6} \atop {x^2-2x+1-2y-4=x^2-1+y}} \right.
\left \{ {{2x-2-2y=6} \atop {x^2-2x+1-2y-4-x^2+1-y=0}} \right.
\left \{ {{2x=6+2+2y} \atop {-2x-2-3y=0}} \right.
\left \{ {{2x=8+2y} \atop {-2x-3y=2}} \right.
\left \{ {{x=4+y} \atop {-2(4+y)-3y=2}} \right.
\left \{ {{x=4+y} \atop {-8-2y-3y=2}} \right.
\left \{ {{x=4+y} \atop {-5y=2+8}} \right.
\left \{ {{x=4+y} \atop {-5y=10}} \right.
\left \{ {{x=4+y} \atop {y=-2}} \right.
\left \{ {{x=4+(-2)} \atop {y=-2}} \right.
\left \{ {{x=2} \atop {y=-2}} \right.
pytaj jak czegoś nie rozumiesz
\frac{2*2-1}{2}-\frac{2*(-2)+1}{2}=\frac{3}{2}-\frac{-3}{2}=\frac{3}{2}+\frac{3}{2}=\frac{6}{2}=3
(2-1)^2-2(-2+2)=(2-1)(2+1)+(-2)
1^2-2*0=1*3-2
1=1