a) [mat]\frac{x+1}{6x^3} * \frac{2x^2}{1-x^2}[/mat]
źródło:
[mat]\frac{x+1}{6x^3}*\frac{2x^2}{1-x^2}=\frac{(x+1)*2x^2}{6x^3(1-x^2)}= \frac{(x+1)2x^2}{6x^3(1-x)(x+1)}=\frac{2x^2}{6x^3(1-x)}=\frac{1}{3x(1-x)}= \frac{1}{-3x^2+3x}[/mat]