\eta = 30\% = 0,3
T_{1} - T_{2} = 100K
T_{1} = ?
T_{2} = ?
\eta = \frac {T_{1} - T_{2}} {T_{1}}
T_{1} = \frac {T_{1} - T_{2}} {\eta} = \frac {100K} {0,3} \approx 333K
T_{1} - T_{2} = 100K
T_{2} = 333K - 100K = 233K
Temp.chłodnicy 233K , temp.nagrzewnicy 333K.