a^{-x}=\frac{1}{a^x}
a) 16^{-2}=\frac{1}{16^2}=\frac{1}{256}
b) 6^{-4}=\frac{1}{6^4}=\frac{1}{1296}
c) 5^{-3}=\frac{1}{5^3}=\frac{1}{125}
d) 1^{-6}=\frac{1}{1^6}=1
(\frac{a}{b})^{-x}=(\frac{b}{a})^x
a) 0,3^{-2}=(\frac{3}{10})^{-2}=(\frac{10}{3})^2=\frac{100}{9}==11\frac{1}{9}
b) (\frac{1}{5})^{-4}=(\frac{5}{1})^4=625
c) 3,75^{-3}=(\frac{375}{100})^{-3}=(\frac{100}{375})^3=\frac{1000000}{52734375}
d) (2 \frac{3}{5})^{-1}=(\frac{13}{5})^{-1}=(\frac{5}{13})^1=\frac{5}{13}
a) 16=2*2*2*2=2^4
b) 8=2*2*2=2^3
c) 64=2*2*2*2*2*2=2^6
d) 128=2*2*2*2*2*2*2=2^7
e) 256=2*2*2*2*2*2*2*2=2^8
a) \frac{1}{4}=(\frac{1}{2})^2
b) \frac{1}{16}=(\frac{1}{2})^4
c) \frac{1}{2}=(\frac{1}{2})^1
d) \frac{1}{256}=(\frac{1}{2})^8
e) 1=(\frac{1}{2})^0