(3-x)^2- (x+ \frac{1}{3})^2= \frac{2}{9}
3^2-2*3*x+x^2- [x^2+ 2*\frac{1}{3}*x+(\frac{1}{3})^2]= \frac{2}{9}
9-6x+x^2- (x^2+ \frac{2}{3}x+\frac{1}{9})= \frac{2}{9}
9-6x+x^2- x^2- \frac{2}{3}x-\frac{1}{9}= \frac{2}{9}
8\frac{8}{9}-6\frac{2}{3}x=\frac{2}{9}
-6\frac{2}{3}x=\frac{2}{9}-8\frac{8}{9}
-6\frac{2}{3}x=-8\frac{6}{9}
-6\frac{2}{3}x=-8\frac{2}{3}
-\frac{20}{3}x=-\frac{26}{3}
x=-\frac{26}{3}*(-\frac{3}{20})
x=\frac{26}{20}=\frac{13}{10}=1\frac{3}{10}=1,3
spr.
(3-1,3)^2- (1,3+ \frac{1}{3})^2= \frac{2}{9}
1,7^2- (1\frac{3}{10}+ \frac{1}{3})^2= \frac{2}{9}
1,7^2- (1\frac{3}{10}+ \frac{1}{3})^2= \frac{2}{9}
2,89-(1\frac{9}{30}+ \frac{10}{30})^2= \frac{2}{9}
2,89-(1\frac{19}{30})^2= \frac{2}{9}
2,89-\frac{2401}{900}= \frac{2}{9}
2,89-2\frac{601}{900}= \frac{2}{9}
2\frac{89}{100}-2\frac{601}{900}= \frac{2}{9}
2\frac{801}{900}-2\frac{601}{900}= \frac{2}{9}
\frac{200}{900}=\frac{2}{9}
\frac{2}{9}=\frac{2}{9}