$(\frac{2}{5}-\frac{7}{8}):(\frac{2}{5}+\frac{7}{8})=$sprowadzamy ułamki do wspólnego mianownika
$=(\frac{28}{40}-\frac{75}{40}):(\frac{28}{40}+\frac{75}{40})=(\frac{16}{40}-\frac{35}{40}):(\frac{16}{40}+\frac{35}{40})=-\frac{19}{40}:\frac{51}{40}=$aby podzielić jeden ułamek przez drugi, należy pierwszy pomnożyć przez odwrotność drugiego
=-\frac{19}{40}*\frac{40}{51}=-\frac{19}{51}
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(\frac{43}{8}+\frac{37}{2}-\frac{173}{24}):\frac{51}{3}=(\frac{43*3}{24}+\frac{37*12}{24}-\frac{173}{24}):\frac{51}{3}=(\frac{129}{24}+\frac{444}{24}-\frac{173}{24}):\frac{51}{3}=\frac{400}{24}:\frac{51}{3}=\frac{400}{24}*\frac{3}{51}=\frac{400}{8*51}=\frac{50}{51}
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(1,4*\frac{5}{14}-0,8):(-\frac{1}{3})^3=(\frac{14}{10}*\frac{5}{14}-0,8):(-\frac{1}{3})^3=(0,5-0,8):-\frac{1}{27}=-0,3*(-\frac{27}{1})=-\frac{3}{10}*(-\frac{27}{1})=\frac{81}{10}=8,1
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\frac{4}{5}-(1,2-\frac{5}{12}-0,8):(-\frac{1}{2})^3=0,8-(1\frac{2}{10}-\frac{5}{12}-\frac{4}{5}):(-\frac{1}{8})=0,8-(1\frac{12}{60}-\frac{25}{60}-\frac{48}{60}):(-\frac{1}{8})=0,8-(\frac{72}{60}-\frac{25}{60}-\frac{48}{60}):(-\frac{1}{8})=0,8-(-\frac{1}{60}):(-\frac{1}{8})=0,8-(-\frac{1}{60})*(-\frac{8}{1})=0,8-7,5=-6,7
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(-10,6+4*\frac{6}{5})*(\frac{8}{5}:1,6)-\frac{\sqrt{36}}{100}=(-10,6+4*1,2)*(1,6:1,6)-\frac{\sqrt{6*6}}{100}=(-10,6+4,8)*1-\frac{6}{100}=-5,8-0,06=-5,86
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