\frac{3}{4}:\frac{1}{4}*3,25=\frac{3}{4}*\frac{4}{1}*3\frac{25}{100}=3*3\frac{25}{100}=9\frac{75}{100}=9,75[ha] zboża ozime
3,25*\frac{2}{3}=\frac{325}{100}*\frac{2}{3}=\frac{325}{50}*\frac{1}{3}=\frac{325}{150}=2\frac{25}{150}=2\frac{1}{6}[ha] zboża jare
9,75+3,25=13[ha] powierzchnia całego pola
13-(9,75+2\frac{1}{6})=13-(9\frac{75}{100}+2\frac{1}{6})=13-(9\frac{3}{4}+2\frac{1}{6})=13-(9\frac{9}{12}+2\frac{2}{12})=13-11\frac{11}{12}=1\frac{1}{12}[ha] rośliny okopowe