[2\frac{5}{6}+\frac{3}{4}:(\frac{2\frac{1}{4}}{3\frac{1}{2}*8-25}-1)]*4\frac{4}{5}=
[2\frac{5}{6}+\frac{3}{4}:(\frac{2,25}{3,5*8-25}-1)]*4\frac{4}{5}=
[2\frac{5}{6}+\frac{3}{4}:(\frac{2.25}{28-25}-1)]*4\frac{4}{5}=
[2\frac{5}{6}+\frac{3}{4}:(0,75-1)]*4\frac{4}{5}=[2\frac{5}{6}+0,75:(-0,25)]*4\frac{4}{5}=(2\frac{5}{6}-3)*\frac{24}{5}=-\frac{1}{6}*\frac{24}{5}=-\frac{24}{30}=-\frac{4}{5}
wynik OK
f)
\frac{(0,5:1,25+1,4:1\frac{4}{7}-\frac{3}{11})*3}{1\frac{3}{4}:18\frac{1}{3}}=\frac{(0,4+1,4:1\frac{4}{7}-\frac{3}{11})*3}{\frac{7}{4}:\frac{55}{3}}=
\frac{(1,8:\frac{11}{7}-\frac{3}{11})*3}{\frac{7}{4}*\frac{3}{55}}=\frac{(\frac{18}{10}*\frac{7}{11}-\frac{3}{11})*3}{\frac{21}{220}}=\frac{(\frac{9}{5}*\frac{7}{11}-\frac{3}{11})*3}{\frac{21}{220}}=
=\frac{(\frac{9}{5}*\frac{7}{11}-\frac{3}{11})*3}{\frac{21}{220}}=\frac{(\frac{63}{55}-\frac{3}{11})*3}{\frac{21}{220}}=\frac{(\frac{63}{55}-\frac{15}{55})*3}{\frac{21}{220}}=
\frac{48}{55}*3*\frac{220}{21}=\frac{48}{55}*\frac{220}{7}=\frac{48}{11}*\frac{44}{7}=48*\frac{4}{7}=
Robiłam f) 2 razy i za każdym razem wychodził mi inny wynik. Kolejność działań zachowana. Sprawdzaj obliczenia.