zadanie 35
Wykonaj podane obliczenia
a)
2^{-3}=(\frac{1}{2})^3=\frac{1}{8}
b)
(-4)^3=-64
c)
(2\frac{1}{2})^2=(\frac{5}{2})^2=\frac{25}{4}=6\frac{1}{4}
d)
(-0,2)^2=-0,2 *(-0,2)=0,04
e)
[(\frac{1}{3})^4*(\frac{2}{3})^{-2}]*9=\frac{1}{3^4}*(\frac{3}{2})^2*9=\frac{1}{81}*\frac{9}{4}*9=\frac{1}{4}
f)
(5^3)^{-2}:(\frac{1}{25})^2=5^{-6}:\frac{1}{5^4}=5^{-6}*5^4=5^{-2}=\frac{1}{25}
g)
\frac{2^{-2}}{2^{-4}}-(\frac{3}{2})^{-3}*(\frac{4}{3})^{-2}=2^{-2-(-4)}-(\frac{2}{3})^3*(\frac{3}{4})^2=2^2-\frac{8}{27}*\frac{9}{16}=4-\frac{1}{6}=3\frac{5}{6}
h)
\frac{(\frac{1}{2})^{-3}}{3^{-3}}=\frac{2^3}{(\frac{1}{3})^3}=8*27=216
zadanie 36
rozwiązanie http://pracadomowa24.pl/zadanie/22892-potegi-dzialania-na-potegach
zadanie 37
Wykonaj podane obliczenia:
a)
(1\frac{1}{2})^{-4}:(1\frac{1}{2})^{-6}=(1\frac{1}{2})^{-4-(-6)}=(\frac{3}{2})^2=\frac{9}{4}=2\frac{1}{4}
b)
(0,2)^5*(2\frac{1}{2})^2=\frac{2^5}{10^5}*\frac{5^2}{2^2}=\frac{2^3}{2^5*5^5}*5^2=2^{3-5}*5^{2-5}=2^{-2}*5^{-3}=\frac{1}{2^2}*\frac{1}{5^3}=\frac{1}{4}*\frac{1}{125}=\frac{1}{500}=0,002
c)
\frac{(-5)^7*(-5)^4}{(-5)^2*(-5)^5}=\frac{(-5)^{11}}{(-5)^{7}}=(-5)^4=625
d)
\frac{(\frac{1}{4})^4*(-8)^4}{5^4*(0,2)^4}=\frac{(-2)^4}{1^4}=16