a)
(3-x)^2-(x+\frac{1}{3})^2=\frac{2}{9}/*9
9(9-6x+x^2)-9(x^2+\frac{2}{3}x+\frac{1}{9})=2
81-54x+9x^2-9x^2-6x-1=2
-60x=-78/:(-60)
x=1,3
b)
(-4x-3)(4x-3)+8(1-\sqrt2x)^2=1
-16x^2+9+8(1-2\sqrt2x+2x^2)=1
-16x^2+9+8-16\sqrt2x+16x^2=1
-16\sqrt2x=-16/:(-16\sqrt2)
x=\frac{1}{\sqrt2}=\frac{\sqrt2}{2}