Obw prostokata ABCD=212+216=56[cm]
obw prostokata A’B’C’D’=42[cm]
Obliczam skale podobieństwa
k=\frac{42}{56}=\frac{3}{4}
a=12cm
a' =12cm*\frac{3}{4}=9cm
b=16cm
b'=16cm*\frac{3}{4}=12cm
Pole prostokata A’B’C’D’=a’ b’=912=108[cm^2]
Odp. Pole prostokata A’B’C’D’wynosi 108[cm^2]