a)
\frac{\sqrt{32}+\sqrt2}{\sqrt2}=\frac{\sqrt{16}*\sqrt2}{\sqrt2}+\frac{\sqrt2}{\sqrt2}=\sqrt{16}+1=4+1=5
albo
\frac{\sqrt{32}+\sqrt2}{\sqrt2}=\frac{\sqrt{16*2}+\sqrt2}{\sqrt2}=\frac{4\sqrt2+\sqrt2}{\sqrt2}=\frac{5\sqrt2}{\sqrt2}=5
b)
\frac{\sqrt{27}-\sqrt{12}}{\sqrt3}=\frac{\sqrt{9*3}-\sqrt{4*3}}{\sqrt3}=\frac{3\sqrt3-2\sqrt3}{\sqrt3}=\frac{\sqrt3}{\sqrt3}=1
c)
\sqrt2(\sqrt8+\sqrt{50})=\sqrt{2*8}+\sqrt{2*50}=\sqrt{16}+\sqrt{100}=4+10=14
d)
\frac{2\sqrt{50}+\sqrt{72}}{2\sqrt2}=\frac{2\sqrt{25*2}+\sqrt{36*2}}{2\sqrt2}=\frac{2*5\sqrt2+6\sqrt2}{2\sqrt2}=\frac{16\sqrt2}{2\sqrt2}=8