e)
\sqrt{3}+\frac{\sqrt{48}}{\sqrt{27}+\sqrt{12}}=\sqrt{3}+\frac{\sqrt{4^2*3}}{\sqrt{3^2*3}+\sqrt{2^*3}}=
\sqrt{3}+\frac{4\sqrt{3}}{3\sqrt{3}+2\sqrt{3}}=\sqrt{3}+\frac{4\sqrt{3}}{5\sqrt{3}}=\sqrt{3}+\frac{4}{5}
A może to ma być tak zapisane:
\frac{\sqrt{3}+\sqrt{48}}{\sqrt{27}+\sqrt{12}}=\frac{\sqrt{3}+4\sqrt{3}}{3\sqrt{3}+2\sqrt{3}}=\frac{5\sqrt{3}}{5\sqrt{3}}=1