Zadanie 11
\sqrt{7 \frac{1}{9}} +\sqrt[3]{216}-(2\sqrt2)^2=\sqrt{\frac{64}{9}}+\sqrt[3]{6^3}-2^2*2=
=\frac{8}{3}+6-8=2\frac{2}{3}+6-8=\frac{2}{3}
Zadanie 12
4\sqrt2=4*1,732=6,928
3\sqrt3+\sqrt2=3*1,732+1,414=4.242+1,732=5,974
-3\sqrt3=-3*1,732=-5,196
2\sqrt3-3\sqrt2=2*1,732-3*1,414=3,464-4,242=-(4,242-3,464)= - \cdots
mnożenie przed dodawaniem