zad. 1
(-1\frac{1}{2})^2=(-\frac{3}{2})^2=\frac{9}{4}=2,25
-8^2=-8*8=-64
(\frac{43}{59})^0=1
(-0,0004)^3=-0,000000000064
\sqrt{1\frac{7}{9}}=\sqrt{\frac{16}{9}}=\frac{4}{3}=1\frac{1}{3}
\sqrt{1,21}=1,1
(\sqrt3)^2=3
\sqrt[3]5)^3=5
\sqrt[3]{3\frac{3}{8}}=\sqrt[3]{\frac{27}{8}}=\frac{3}{2}=1,5
\sqrt[3]{-\frac{64}{125}}=-\frac{4}{5}
zad. 2
(-2)^2*(-2)^3=(-2)^5=-32
(1\frac{1}{6})^3:(\frac{7}{6})^3=(\frac{7}{6}:\frac{7}{6})^3=1^3=1
(2,5*0,04)^2=(0,1)^2=0,1*0,1=0,01
(-0,2)^7*5^7=(-0,2*5)^7=(-1)^7=-1
4^{11}*(0,25)^{11}=(4*0,25)^{11}=1^{11}=1
(0,002)^8*(-0,5)^8=[0,002*(-0,5)]^8=(-0,001)^8=[(0,1)^3]^8=(0,1)^{24}=[1*10^{-1}]^{24}=1*10^{-24}=10^{-24}
minus do potęgi ósmej daje plus (8 liczbą parzystą)