g)
3(2x+a)(3x+2)-2(3x+1)^2=43
x=1
3(2*1+a)(3*1+2)-2(3*1+1)^2=43
3(2+a)(3+2)-2(3+1)^2=43
3(2+a)(3+2)-2(3+1)^2=43
(6+3a)*5-2*4^2=43
30+15a-32=43
-2+15a=43 |+2
15a=45 |:15
a = 3
h)
\frac{ax-5}{6} + \frac{x+a}{4} = \frac{5-ax}{3} - \frac{3a -7x}{4} - x
dla x = 1
\frac{a*1-5}{6} + \frac{1+a}{4} = \frac{5-a*1}{3} - \frac{3a -7*1}{4} - 1
\frac{a-5}{6} + \frac{1+a}{4} = \frac{5-a}{3} - \frac{3a -7}{4} - 1 |*12
2(a-5)+3(1+a)=4(5-a)-3(3a-7)-12
2a-10+3+3a=20-4a-9a+21-12
5a-7=-13a+29
18a=36 |:18
a = 2