Zadanie 2
(x-a)^2+(y-b)^2=r^2
a)
x^2+(y+2)^2=16
(x^2-0)^2+[y-(-2)]^2=4^2
S(a,b) = (0,-2) , r=4
b)
(x-4)^2+(y+2)^2=8
a = 4 , b = - 2 => S(a,b) = (4, -2)
r^2=8 => r=\sqrt8=2\sqrt2
c)
x^2+y^2-2x-6y+9=0
x^2-2x+(y^2-6y+9)=0
x^2-2x+1-1+(y-3)^2=0
x^2-2x+1+(y-3)^2=1
(x-1)^2+(y-3)^2=1^2
a = 1 , b = 3 , r = 1
S(a,b) = (1,3) , r = 1 <-- odpowiedź