a)
\frac{2^{-2}+5^0}{(0,5)^{-2}-5*(-2)^{-2}+(\frac{2}{3})^{-2}}+4,75=\frac{(\frac{1}{2})^2+1}{(\frac{1}{2})^{-2}-5*(-\frac{1}{2})^2+(\frac{3}{2})^2}+4,75=
=\frac{\frac{1}{4}+\frac{4}{4}}{2^2-5*\frac{1}{4}+\frac{9}{4}}+4,75=\frac{\frac{5}{4}}{4-\frac{5}{4}+\frac{9}{4}}+4,75=\frac{\frac{5}{4}}{\frac{16-5+9}{4}}+4,75=
=\frac{\frac{5}{4}}{\frac{20}{4}}+4,75=\frac{\frac{5}{4}}{5}+4,75=\frac{5}{4}*\frac{1}{5}+4,75=\frac{1}{4}=4,75=5
b)
\frac{(0,6)^0-(0,1)^{-1}}{(3:2^3)^{-1}*(1,5)^3-(-\frac{1}{3})^{-1}}=\frac{1-(\frac{1}{10})^{-1}}{(\frac{3}{8})^{-1}*(\frac{3}{2})^3-(-3)}=\frac{1-10}{\frac{8}{3}*\frac{27}{8}+3}=
=\frac{-9}{9+3}=-\frac{9}{12}=-0,75