doprowadz do najprostszej postaci wyrażenie
\frac{ \sqrt3+\sqrt2 }{ \sqrt3-\sqrt2 }-\frac{\sqrt3-\sqrt2 }{\sqrt3+\sqrt2 }+\frac{1-16\sqrt6}{4}=
=\frac{(\sqrt3+\sqrt2) (\sqrt3+\sqrt2) }{(\sqrt3-\sqrt2) (\sqrt3+\sqrt2) }-\frac{(\sqrt3-\sqrt2)(\sqrt3-\sqrt2) }{(\sqrt3+\sqrt2)(\sqrt3-\sqrt2) }+\frac{1-16\sqrt6}{4}=
=\frac{ (\sqrt3)^2+2\sqrt3\sqrt2+(\sqrt2)^2 }{ (\sqrt3)^2-(\sqrt2)^2 }-\frac{(\sqrt3)^2-2\sqrt3\sqrt2+(\sqrt2)^2 }{(\sqrt3)^2-(\sqrt2)^2 }+\frac{1-16\sqrt6}{4}=
=\frac{ 3+2\sqrt{3*2}+2 }{ 3-2 }-\frac{3-2\sqrt{3*2}+2 }{3-2 }+\frac{1-16\sqrt6}{4}=
=3+2\sqrt6+2-(3-2\sqrt6+2)+\frac{1-16\sqrt6}{4}=
=3+2\sqrt6+2-3+2\sqrt6-2+\frac{1-16\sqrt6}{4}=\frac{4*4\sqrt6}{4}+\frac{1-16\sqrt6}{4}=
=\frac{16\sqrt6+1-16\sqrt6}{4}=\frac{1}{4}=0,25