Jeśli treść zadania jest taka
(1\frac{1}{2}-3\frac{1}{3}):(1\frac{1}{9}-2\frac{1}{2})=(\frac{3}{2}-\frac{10}{3}):(\frac{10}{9}-\frac{5}{2})=
=(\frac{9}{6}-\frac{20}{6}):(\frac{20}{18}-\frac{45}{18})=-\frac{11}{6}:(-\frac{25}{18})=\frac{11*18}{6*25}=\frac{33}{25}=1\frac{8}{25}
lub taka treść
1\frac{1}{2}-3\frac{1}{3}:(1\frac{1}{9}-2\frac{1}{2})=1,5-3\frac{1}{3}:(\frac{10}{9}-\frac{5}{2})=1,5-3\frac{1}{3}:(-\frac{25}{18})=
=1,5+\frac{10*18}{3*25}=
=1,5+\frac{12}{5}=1,5+2,4=3,9