zad. 3.124 a i 3.125 a
potega-o-wykladniku-wymiernym/ - rozwiązania
Zadanie 3.125
b)
\frac{15*5^{\frac{7}{6}}-50\sqrt[6]{0,2^{-1}}}{625^{-\frac{1}{6}}*5^{-\frac{4}{3}}:25^{-\frac{3}{2}}}=
=\frac{3*5*5^{\frac{7}{6}}-2*5^2*5^{\sqrt[6]{\frac{10}{2}}}}{(5^4)^{-\frac{1}{6}}*5^{-\frac{4}{3}}:(5^2)^{-\frac{3}{2}}}=
=\frac{3*5*5^{\frac{7}{6}}-2*5^2*5^{\frac{1}{6}}}{5^{-\frac{2}{3}-\frac{4}{3}}:5^{-3}}=
=\frac{3*5^{1\frac{7}{6}}-2*5^{2\frac{1}{6}}}{5^{-\frac{6}{3}-3}}=\frac{3*5^{\frac{13}{6}}-2*5^{\frac{13}{6}}}{5^{-2-(-3)}}=
=\frac{5^{\frac{13}{6}}(3-2)}{5}=5^{\frac{13}{6}-1}=5^{\frac{13-6}{6}}=5^{\frac{7}{6}}