b)
\frac{2}{2x+3}-1=\frac{2x}{2x-3}
\frac{2-2x-3}{2x+3}=\frac{2x}{2x-3}
\frac{-2x-1}{2x+3}=\frac{2x}{2x-3}
2x-3\ne0 i 2x+3\ne0
2x\ne3 i 2x\ne-3
x\ne \frac{3}{2}
x\ne- \frac{3}{2}
(-2x-1)(2x-3)=2x(2x+3)
-4x^2+6x-2x+3=4x^2+6x
-4x^2-4x^2+4x-6x+3=0
-8x^2-2x+3=0
\Delta=(-2)^2-4*(-8)*3=4+96=100
\sqrt{\Delta}=\sqrt{100}=10
x_1=\frac{2-10}{2*(-8)}=\frac{-8}{-16}=\frac{1}{2}
x_2=\frac{2+10}{2*(-8)}=-\frac{12}{16}=-\frac{3}{4}