zadanie 4.
2^{-3}=\frac{1}{2^3}=\frac{1}{8}
(\frac{1}{2})^{-2}=(\frac{2}{1})^2=4
(-3)^{-2}={\frac{1}{(-3)^2}}=\frac{1}{9}
(-1)^{-1}=\frac{1}{(-1)^1}=-14
(2\frac{1}{3})^{-1}=(\frac{7}{3})^{-1}=\frac{3}{7}
(-1)^{-4}=\frac{1}{(-1)^4}=1
(1\frac{3}{4})^{-1}=(\frac{7}{4})^{-1}=\frac{4}{7}
0,2^{-1}=(\frac{2}{10})^{-1}=(\frac{1}{5})^{-1}=5