tg 30=\frac{1}{\sqrt3}
ctg30=\sqrt3
4ctg^230-tg^230=4*(\sqrt3)^2-(\frac{1}{\sqrt3})^2=4*3- \frac{1}{3} =12-\frac{1}{3}=11\frac{2}{3}
sin60*cos30+sin45*cos45=\frac{\sqrt3}{2}*\frac{\sqrt3}{2}+\frac{\sqrt2}{2}*\frac{\sqrt2}{2}=\frac{3}{4}+\frac{2}{4}=\frac{5}{4}=1,25