Zad. 3.127
a)
=[\sqrt{4-\sqrt{12}}+\sqrt{4+\sqrt{12}}]^2=
wzór
(a+b)^2=a^2+2ab+b^2
=4-\sqrt{12}+2\sqrt{(4-\sqrt{12})(4+\sqrt{12})}+4+\sqrt{12}=
=8+2\sqrt{16-12}=8+2*2=12
b)
=(\sqrt{6-\sqrt{20}}-\sqrt{6+\sqrt{20}})^2=
=6-\sqrt{20}-2\sqrt{(6-\sqrt{20})(6+\sqrt{20}})+6+\sqrt{20}=
=12-2\sqrt{36-20}=12-2*4=4
c)
=(\sqrt{6-\sqrt{11}}+\sqrt{6+\sqrt{11}})^2=6-\sqrt{11}+2\sqrt{36-11}+6+\sqrt{11}=12+2*5=22
d)
=(\sqrt{7+\sqrt{24}}-\sqrt{7-\sqrt{24}})^2=7+\sqrt{24}-2\sqrt{49-24}+7-\sqrt{24}=
==14-2+5=4