Zad. 2
V_{ garnka}=\pi r^2*h=\pi *9^2*24=\pi* 81*24=1944 \pi(cm^3)
V_{wody}=\frac{3}{4}*1944 \pi=0,75*1944 \pi=1458\pi(cm^3)
szukane r
\pi r^2*h=1458\pi/:\pi
r^2*25=1458
r^2=1458:25
r^2=58,32
r=\sqrt{58,32}\approx7,6367532\approx7,64(cm) odp.
Spr.
\pi r^2*h=\pi *58,37*25\approx1459,25\pi (cm^3)
1459,25\pi >1458\pi