c)
x=(\frac{1}{2})^{-1}=2
=4x^2+4x+1-(x^3+1)=4x^2+4x+1-x^3-1=
=-x^3+4x^2+4x=-2^3+4*2^2+4*2=-8+16+8=16
d)
x=(5\frac{5}{9})^{\frac{1}{2}}=\sqrt{\frac{50}{9}}=\frac{5\sqrt2}{3}
=x^2-4x+4-(x^3-2^3)=x^2-4x+4-x^3+8
=-x^3+x^2-4x+12=-(\frac{5\sqrt2}{3})^3+(\frac{5\sqrt2}{3})^2-4*\frac{5\sqrt2}{3}+12=
=-\frac{125*2\sqrt2}{27}+\frac{50}{9}-\frac{20\sqrt2}{3}+12=
=-\frac{250\sqrt2}{27}+5\frac{5}{9}-\frac{180\sqrt2}{27}+12=17\frac{5}{9}-\frac{430\sqrt2}{27}=
=17\frac{5}{9}-15\frac{25}{27}\sqrt2