\frac{27}{10}+x-\frac{3}{4}y=2x-y+\frac{5}{3}
10x-10y-(4-4x)*\frac{1}{3}=y|*3
x-2x-\frac{3}{4}y+y=\frac{50}{30}-\frac{81}{30}
30x-30y-4+4x=3y
-x+\frac{1}{4}y=-\frac{31}{30}|*120
34x-33y=4
-120x+30y=-124
x=\frac{4+33y}{34}
I równanie
-120*\frac{4+33y}{34}-33y=4
\frac{-480}{34}-\frac{3960}{34}y-33y=4
-\frac{3960}{34}y-\frac{1122}{34}y=\frac{136}{34}+\frac{480}{34}
-\frac{5082}{34}y=\frac{616}{34}
y=-8\frac{1}{4}
Zatem
x=\frac{4+33*(-8\frac{1}{4})}{34}=\frac{4-\frac{1089}{4}}{34}=-\frac{1073}{4}*\frac{1}{34}=-\frac{1073}{136}