\frac{2(sin^215^0+cos^215^0)-3tg30^0}{2sin45^0}
źródło:
\frac{2(sin^215^0+cos^215^0)-3tg30^0}{2sin45^0}=
=\frac{2*1-3*\frac{\sqrt3}{3}}{2*\frac{\sqrt2}{2}}=\frac{2-\sqrt3}{\sqrt2}*\frac{\sqrt2}{\sqrt2}=\frac{2\sqrt2-\sqrt6}{2}