rozwiązania
a)
\sqrt[3]{27+64+125}=\sqrt[3]{216}=\sqrt[3]{6^3}=6
b)
\sqrt{25}-\sqrt{16}+\sqrt[3]{27}=5-4+3=4
c)
\sqrt[3]{-343}+\sqrt{1,96}-\sqrt[3]{2,744}=\sqrt[3]{-7^3}+\sqrt{1,4^2}-\sqrt[3]{1,4^3}=-7+1,4-1,4=-7
d)
\sqrt{144}+\sqrt[3]{72+144}=12+\sqrt[3]{216}=12+\sqrt[3]{2^3*3^3}=12+2*3=18
----------------------------
216|2
108|2
54 |2
27 |3
9 | 3
3 | 3
1 |
216=2^3*3^3=6^3