Zadanie \frac{2^{4a-2}*4^{a+2}}{2^a*16^{a-1}}
źródło:
\frac{2^{4a-2}*4^{a+2}}{2^a*16^{a-1}}=\frac{2^{4a-2}*(2^2)^{a+2}}{2^a*(2^4)^{a-1}}=
=\frac{2^{4a-2}*2^{2a+4}}{2^a*2^{4a-4}}=\frac{2^{4a-2+2a+4}}{2^{a+4a-4}}=\frac{2^{6a+2}}{2^{5a-4}}=
=2^{6a+2-(5a-4)}=2^{6a+2-5a+4}=2^{a+6}