Zadanie 1
\frac{9^3*3^{\frac{3}{2}}}{\sqrt{27}}=\frac{(3^2)^3*3^{\frac{2}{3}}}{(3^3)^{\frac{1}{2}}}=\frac{3^6*3^{\frac{3}{2}}}{3^{\frac{3}{2}}}=3^6
odpowiedź A
Zadanie 2
(\sqrt2-\sqrt3)^2-(2\sqrt3+\sqrt2)^2=2-2\sqrt6+3-(4*3+4\sqrt6+2)=
5-2\sqrt6-(4\sqrt6+14)=5-2\sqrt6-4\sqrt6-14=-6\sqrt6-9=-3(2\sqrt6+3)
odpowiedź C
Zadanie 8
\sqrt[3]{2\frac{10}{27}}-(\frac{3}{4})^{-1}:(-1,2)^2=\sqrt[3]{\frac{64}{27}}-\frac{4}{3}:1,44=\frac{4}{3}-\frac{4}{3}:\frac{144}{100}=
\frac{4}{3}-\frac{4}{3}*\frac{100}{144}=\frac{4}{3}-\frac{100}{108}=\frac{144-100}{108}=\frac{44}{108}=\frac{11}{27}
Zadanie 12
\frac{(0,02*10^8)*(3*10^{-6})}{0,6*10^{10}}=\frac{0,06*10^2}{0,6*10^{10}}=0,1*10^{-8}=1*10^{-1}*10^{-8}=1*10^{-9}