a)
x^{-\frac{3}{4}}=\frac{1}{8}
x^{-\frac{3}{4}}=(\frac{1}{2})^3 |()^{-\frac{4}{3}}
x^{-\frac{3}{4}*(-\frac{4}{3})}=(\frac{1}{2})^{3*(-\frac{4}{3})}
x=(\frac{1}{2})^{-4}
x=2^4=16
b)
(3x^{\frac{3}{2}})^{-1}=24^{-1} |()^{-1}
3x^{\frac{3}{2}}=24 |:3
x^{\frac{3}{2}}=8 |()^2
x^3=64
x=4
c.
x^{\frac{4}{3}} = 3\sqrt[3]{3}
x^{\frac{4}{3}}=3^1*3^{\frac{1}{3}}
x^{\frac{4}{3}}=3^{\frac{3+1}{3}}
x^{\frac{4}{3}}=3^{\frac{4}{3}}
x=3